(317, 200)
(195, 100)
(98, 0)
if the following three points are on a curve, likely a parabola, and the rest of the line reflects this sort of change in rate... what would you call this, and, a question that's fairly old but huge - is there a formula to find other points on the line? normally, i can come up with formulas out of nowhere, but suddenly, i'm blank. the provided points were generated off of something i'm working on - but they're more of an example than anything. rather than an answer, i would strongly like to know - what is this, and how would one solve it? they are, of course, equidistant on the y-axis.
very old mathematical question
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Re: very old mathematical question
Oh my god, I haven't taken Trigonometry in over ten years. I think I need to brush up.
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Re: very old mathematical question
Yep. I have no clue. I am useless at math. 

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Re: very old mathematical question
Isn't that a bezier curve?
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Re: very old mathematical question
that was one of the previous assumptions i had made; in this scenario, all three points are on the line, and represent the rate of curvature. it's almost comparable to exponential or logarithmic curves, or segments of them.kodi wrote:Isn't that a bezier curve?
it's almost like, if one draws two lines out of a point; one goes straight up, and the other goes off to the side, but slowly curves upwards with the perfectly straight one; one could make two points at the same height on both lines, but the distance between these points would change at a certain rate, and finding this rate is my goal (i apologize for the kind of less-descriptive original post...)

this is a quick illustration of the two lines scenario; if the difference in the x-values of these are combined with the y-values in the coordinates, it would form what i'm trying to describe (if that is, in fact, a bezier curve, it all goes to show that i really needed this thread
it's not a clean parabola, but i have little clue how to use the paint line tool with curves (it's also possible that i forgot exactly what shape to draw...

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Re: very old mathematical question
Well the graph you drew looks more like something along the lines of
x + (x*0.02)^4 [or "x + (x*0.005)^8" for an even sharper spike]
Where the "go fucking nuts" exponential growth is delayed through making the number that is being raised in powers (me not good at math in english) progress slower through abusing a 0<n<1 multiplication.
Seemingly this is part of what people use for fast 3D graphics rendering when trying to make glossy materials have sharp light spread, since it's a neat approximation of a sudden spike in brightness.
x + (x*0.02)^4 [or "x + (x*0.005)^8" for an even sharper spike]
Where the "go fucking nuts" exponential growth is delayed through making the number that is being raised in powers (me not good at math in english) progress slower through abusing a 0<n<1 multiplication.
Seemingly this is part of what people use for fast 3D graphics rendering when trying to make glossy materials have sharp light spread, since it's a neat approximation of a sudden spike in brightness.
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Re: very old mathematical question
I don't understand the question, since with three distinct and misaligned point you can generate an unique parabola and also an unique circumference...
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Re: very old mathematical question
i blame my poor graphic... i meant parabolas in this case. one big element of the question is the fact that these points would all be on the line, as most of the formulas i find derive their curve or parabola from surrounding points. i don't have enough of a mathematical education to be extremely clear about it, but if this does seem like a question you'd be interested in answering, i could try to provide more informationEdward-san wrote:I don't understand the question, since with three distinct and misaligned point you can generate an unique parabola and also an unique circumference...
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Re: very old mathematical question
Sorry, I'm a bit lost on the question. Anyways, by 'would all be on the line' do you mean the straight line or a curved line? There's quite a difference, because the points at the top post aren't on a straight line.
Let's call the points A = (317, 200), B = (195, 100) and C = (98, 0). If you calculate the slope of AB and BC, they don't match.
Slope formula:
mAB = (200-100)/(317-195) = 100/122
mBC = (100-0)/(195-98) = 100/97
Let's call the points A = (317, 200), B = (195, 100) and C = (98, 0). If you calculate the slope of AB and BC, they don't match.
Slope formula:
mAB = (200-100)/(317-195) = 100/122
mBC = (100-0)/(195-98) = 100/97