Arrays for dummies

[Travis]

Alright, up until this point, I've only used arrays for strings. I never even realised it would be possible to store integers within them. After doing a few searches and looking through about 15 threads, I'm still a little confused.

Let me get a few things straight here.

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int arrayfour[4];

Sets four integers... 0, 0, 0, 0. Correct? So that would mean....

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script 02 open
{
    arrays[1]=8;
}

Would make 0, 8, 0, 0. Correct?

That all being said, would it be possible to get the amount of integers in an array that equal a number? For example, you have an array of 7 integers, and 3 of those integers = 2. How would I get that 3? The closest thing I can get is something like this, but it isn't quite working properly...

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numbers = (arrayseven[0 && 1 && 2 && 3 && 4 && 5 && 6 && 7]==2);

[TheDarkArchon]

arrays[7] = {2};, IIRC.

[Necromage]

In order to do that you will have to something like this:

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for(int i = 0; i < 7; i++)
         if(arrays[i] == 2) numbers++;

What this says is that for every integer, i, less then seven and starting at 0, I want to know if the value of arrays is equal to 2 and if so add 1 to numbers.

[HotWax]

After declaration, you can only access one member of an array at a time. That's why you have to do something like what Necro posted.

[TheDarkArchon]

Mine was supposed to be a declaration, though I made a couple of gaffs (missing ";" and missing "int" prefix).

[Travis]

After declaration, you can only access one member of an array at a time. That's why you have to do something like what Necro posted.

Argh. That's gonna be a problem, since I'm looking for something that constantly moniters an array.

Thanks for the efforts though, I'll play around with what you've given me a bit here...

[durnurd]

What's wrong with the code Necro gave?

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script 5 (void)
{
   int numbers = 0;
   for(int i = 0; i < 7; i++)
      if(arrays[i] == 2) numbers++;
   if (numbers == 3)
      dosomething();
   restart;
}

[HotWax]

Argh. That's gonna be a problem, since I'm looking for something that constantly moniters an array.

Hey, don't worry about it. Modern computers are lightning-fast little beasties.

This script will display a constantly-updated count of the number 2 within an array of 100 values:

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int MyArray[100];

script 200 ENTER {
     int Count, i;

     while (1) {
          for (i=0; i<100; i++) if (MyArray[i] == 2) Count++;

          Print(s:"Current count: ", n:Count);
          delay(1);
     }
}

This shouldn't faze ZDoom at all, even though it's running the loop 100 times per tic (3500 times a second).

Mine was supposed to be a declaration, though I made a couple of gaffs (missing ";" and missing "int" prefix).

To my knowledge you cannot assigned an entire array to a single number. Your code would assign the number 2 to the 0th element of the array and leave the rest as 0's.

However, you can do something like this:

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int ArrayOfTwos[8] = { 2, 2, 2, 2, 2, 2, 2, 2 };
int MixedArray[10] = { 3, 1, 8, 2, 5, 0, -2, 4, 3, 0 };
int StringAndIntsCauseACSRox[5] = {
     17,
     "Charlie",
     "Brown",
     -2,
     0
};

[Travis]

Bear with me here, guys. You all appear to think that necro's code is what should work, which it doesnt...meaning I'm most likely doing something wrong elsewhere. Let me go back and troubleshoot a few minutes...I'll edit this post if I can't seem to get it working.

EDIT:: Yeah, I'm just not getting it. I'm using your script, Hotwax, and it's just constantly adding to the Count int.

EDIT 2:: Nevermind, guys, I got a system workin' on my own. I appreciate all the help though!

[HotWax]

Stupid forum bug deleted my post (grumble, grumble).

EDIT:: Yeah, I'm just not getting it. I'm using your script, Hotwax, and it's just constantly adding to the Count int.

That's because I made a noobie mistake.

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while (1) {
     Count = 0; // <-- Add this line
     for (i=0; i<100; i++) if (MyArray[i] == 2) Count++; 

     Print(s:"Current count: ", n:Count); 
     delay(1); 
}